RenegadeRaven Posted February 11, 2018 Share Posted February 11, 2018 (edited) How do I convert *.pkx to *.ekx, x being 4, 5, 6, or 7? I'm trying to write a program in Visual Basic, and I need it to be able to encrypt *.pkx files into *.ekx files. The problem is I can't figure out how. Edited February 11, 2018 by Regnum Link to comment Share on other sites More sharing options...
theSLAYER Posted February 11, 2018 Share Posted February 11, 2018 1 hour ago, Regnum said: How do I convert *.pkx to *.ekx, x being 4, 5, 6, or 7? I'm trying to write a program in Visual Basic, and I need it to be able to encrypt *.pkx files into *.ekx files. The problem is I can't figure out how. Gen IV and V Read up on PKM structure, and see checksum. And how the system got minor updates in Gen VI and VII Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 11, 2018 Author Share Posted February 11, 2018 35 minutes ago, theSLAYER said: Gen IV and V Read up on PKM structure, and see checksum. And how the system got minor updates in Gen VI and VII I had looked at those, it’s that I don’t know how to apply the formulas written there. Link to comment Share on other sites More sharing options...
theSLAYER Posted February 11, 2018 Share Posted February 11, 2018 4 minutes ago, Regnum said: I had looked at those, it’s that I don’t know how to apply the formulas written there. The shuffling order formula is basically:dim order as integer = (pid >> (13) And 31) Mod 24 and the horrible implementation for order shuffling I did a long time ago: Spoiler Select Case order Case 0 firstblock = "A" secondblock = "B" thirdblock = "C" fourthblock = "D" Case 1 firstblock = "A" secondblock = "B" thirdblock = "D" fourthblock = "C" Case 2 firstblock = "A" secondblock = "C" thirdblock = "B" fourthblock = "D" Case 3 firstblock = "A" secondblock = "D" thirdblock = "B" fourthblock = "C" Case 4 firstblock = "A" secondblock = "C" thirdblock = "D" fourthblock = "B" Case 5 firstblock = "A" secondblock = "D" thirdblock = "C" fourthblock = "B" Case 6 firstblock = "B" secondblock = "A" thirdblock = "C" fourthblock = "D" Case 7 firstblock = "B" secondblock = "A" thirdblock = "D" fourthblock = "C" Case 8 firstblock = "C" secondblock = "A" thirdblock = "B" fourthblock = "D" Case 9 firstblock = "D" secondblock = "A" thirdblock = "B" fourthblock = "C" Case 10 firstblock = "C" secondblock = "A" thirdblock = "D" fourthblock = "B" Case 11 firstblock = "D" secondblock = "A" thirdblock = "C" fourthblock = "B" Case 12 firstblock = "B" secondblock = "C" thirdblock = "A" fourthblock = "D" Case 13 firstblock = "B" secondblock = "D" thirdblock = "A" fourthblock = "C" Case 14 firstblock = "C" secondblock = "B" thirdblock = "A" fourthblock = "D" Case 15 firstblock = "D" secondblock = "B" thirdblock = "A" fourthblock = "C" Case 16 firstblock = "C" secondblock = "D" thirdblock = "A" fourthblock = "B" Case 17 firstblock = "D" secondblock = "C" thirdblock = "A" fourthblock = "B" Case 18 firstblock = "B" secondblock = "C" thirdblock = "D" fourthblock = "A" Case 19 firstblock = "B" secondblock = "D" thirdblock = "C" fourthblock = "A" Case 20 firstblock = "C" secondblock = "B" thirdblock = "D" fourthblock = "A" Case 21 firstblock = "D" secondblock = "B" thirdblock = "C" fourthblock = "A" Case 22 firstblock = "C" secondblock = "D" thirdblock = "B" fourthblock = "A" Case 23 firstblock = "D" secondblock = "C" thirdblock = "B" fourthblock = "A" End Select Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 11, 2018 Author Share Posted February 11, 2018 1 hour ago, theSLAYER said: The shuffling order formula is basically:dim order as integer = (pid >> (13) And 31) Mod 24 and the horrible implementation for order shuffling I did a long time ago: Reveal hidden contents Select Case order Case 0 firstblock = "A" secondblock = "B" thirdblock = "C" fourthblock = "D" Case 1 firstblock = "A" secondblock = "B" thirdblock = "D" fourthblock = "C" Case 2 firstblock = "A" secondblock = "C" thirdblock = "B" fourthblock = "D" Case 3 firstblock = "A" secondblock = "D" thirdblock = "B" fourthblock = "C" Case 4 firstblock = "A" secondblock = "C" thirdblock = "D" fourthblock = "B" Case 5 firstblock = "A" secondblock = "D" thirdblock = "C" fourthblock = "B" Case 6 firstblock = "B" secondblock = "A" thirdblock = "C" fourthblock = "D" Case 7 firstblock = "B" secondblock = "A" thirdblock = "D" fourthblock = "C" Case 8 firstblock = "C" secondblock = "A" thirdblock = "B" fourthblock = "D" Case 9 firstblock = "D" secondblock = "A" thirdblock = "B" fourthblock = "C" Case 10 firstblock = "C" secondblock = "A" thirdblock = "D" fourthblock = "B" Case 11 firstblock = "D" secondblock = "A" thirdblock = "C" fourthblock = "B" Case 12 firstblock = "B" secondblock = "C" thirdblock = "A" fourthblock = "D" Case 13 firstblock = "B" secondblock = "D" thirdblock = "A" fourthblock = "C" Case 14 firstblock = "C" secondblock = "B" thirdblock = "A" fourthblock = "D" Case 15 firstblock = "D" secondblock = "B" thirdblock = "A" fourthblock = "C" Case 16 firstblock = "C" secondblock = "D" thirdblock = "A" fourthblock = "B" Case 17 firstblock = "D" secondblock = "C" thirdblock = "A" fourthblock = "B" Case 18 firstblock = "B" secondblock = "C" thirdblock = "D" fourthblock = "A" Case 19 firstblock = "B" secondblock = "D" thirdblock = "C" fourthblock = "A" Case 20 firstblock = "C" secondblock = "B" thirdblock = "D" fourthblock = "A" Case 21 firstblock = "D" secondblock = "B" thirdblock = "C" fourthblock = "A" Case 22 firstblock = "C" secondblock = "D" thirdblock = "B" fourthblock = "A" Case 23 firstblock = "D" secondblock = "C" thirdblock = "B" fourthblock = "A" End Select Thanks. Now, how do I use the formula, X[n+1] = (0x41C64E6D * X[n] + 0x6073), what do I put for X[n] and X[n+1]? Link to comment Share on other sites More sharing options...
theSLAYER Posted February 11, 2018 Share Posted February 11, 2018 18 minutes ago, Regnum said: Thanks. Now, how do I use the formula, X[n+1] = (0x41C64E6D * X[n] + 0x6073), what do I put for X[n] and X[n+1]? These are the functions I have relating to rand and the seed generation: Spoiler Public seed As UInt32 Public Sub srnd(ByVal newSeed As UInt32) seed = newSeed End Sub Public Function rand() As UInt32 seed = (((&H41C64E6D * seed) + &H6073)) And &HFFFFFFFF Return seed >> 16 End Function So at every instance that you block xor rand(), the rand will give the updated random number as per the game's RNG. I'm pretty sure I got help for this a long time ago, but I can't remember from who. In any case, that is how it is done (edit: I think I use the srnd function relating to checksum) Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 11, 2018 Author Share Posted February 11, 2018 6 minutes ago, theSLAYER said: These are the functions I have relating to rand and the seed generation: Reveal hidden contents Public seed As UInt32 Public Sub srnd(ByVal newSeed As UInt32) seed = newSeed End Sub Public Function rand() As UInt32 seed = (((&H41C64E6D * seed) + &H6073)) And &HFFFFFFFF Return seed >> 16 End Function So at every instance that you block xor rand(), the rand will give the updated random number as per the game's RNG. I'm pretty sure I got help for this a long time ago, but I can't remember from who. In any case, that is how it is done (edit: I think I use the srnd function relating to checksum) Is seed the checksum? Link to comment Share on other sites More sharing options...
theSLAYER Posted February 11, 2018 Share Posted February 11, 2018 2 minutes ago, Regnum said: Is seed the checksum? No, seed is the value that is used to seed the RNG. function rand()'s seed shows the same equation as the one you asked me. edit: let me show you part of my encrypt function Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 11, 2018 Author Share Posted February 11, 2018 Just now, theSLAYER said: No, seed is the value that is used to seed the RNG. If you notice, seed is the same equation as the one you asked me. So, where does the checksum come in? Link to comment Share on other sites More sharing options...
theSLAYER Posted February 11, 2018 Share Posted February 11, 2018 17 minutes ago, Regnum said: So, where does the checksum come in? here, Lemme show you: Spoiler Public Function encrypt(ByVal pkm() As Byte) 'variables here 'stuff happens here 'such as Shuffle the blocks using the block shuffling algorithm above. 'Seed the PRNG with the checksum (let X[n] be the checksum), srnd(checksum) 'finally, Sequentially, for each 2-byte word Y from 0x08 to 0x87, apply the transformation: unencryptedByte = Y xor rand() 'example: Select Case firstblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While 'remainder of code Return pkm End Function so srnd(checksum) uses checksum as seed. Rand() will call a new value. and remainder rand()s in the function doesn't need to be reseeded using the checksum. edit: so what I'm trying to say is that the variable seed isn't always the checksum. You only seed the checksum upon initial encryption of that particular Pokemon (for it's first block), and it new result will be reused to seed the RNG for the remainder 3 blocks. I can give you my full function to refer to if needed. Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 11, 2018 Author Share Posted February 11, 2018 15 minutes ago, theSLAYER said: here, Lemme show you: Hide contents Public Function encrypt(ByVal pkm() As Byte) 'variables here 'stuff happens here 'such as Shuffle the blocks using the block shuffling algorithm above. 'Seed the PRNG with the checksum (let X[n] be the checksum), srnd(checksum) 'finally, Sequentially, for each 2-byte word Y from 0x08 to 0x87, apply the transformation: unencryptedByte = Y xor rand() 'example: Select Case firstblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While 'remainder of code Return pkm End Function So like this: 'block shuffling stuff srnd(chksum) rand() Link to comment Share on other sites More sharing options...
theSLAYER Posted February 11, 2018 Share Posted February 11, 2018 1 minute ago, Regnum said: So like this: 'block shuffling stuff srnd(chksum) rand() That's the main gist. Seed the RNG first with checksum srnd(checksum), then apply transformation byte xor rand. When you read the wiki, it says " Sequentially, for each 2-byte word Y from 0x08 to 0x87, apply the transformation " So you're not just rand() once, you'll have to rand() for every byte you xor against. Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 11, 2018 Author Share Posted February 11, 2018 I was able to find this: PKM Encrypt.cs Problem is I don't understand C#. Link to comment Share on other sites More sharing options...
theSLAYER Posted February 11, 2018 Share Posted February 11, 2018 10 minutes ago, Regnum said: I was able to find this: PKM Encrypt.cs Problem is I don't understand C#. The code I gave you is in Visual Basic .net its okay if you don't understand C#, just use online converters Link to comment Share on other sites More sharing options...
theSLAYER Posted February 11, 2018 Share Posted February 11, 2018 @Regnum This is my encrypt code. Since this was made years back, there's probably definitely better ways to optimize the code, so you can keep that in mind if you're gonna adapt it. Spoiler Public Function encrypt(ByVal pkm() As Byte) Dim pid As UInt32 = 0 Dim checksum As UInt16 = 0 pid = BitConverter.ToUInt32(pkm, 0) checksum = BitConverter.ToUInt16(pkm, 6) Dim order As Integer = (pid >> (13) And 31) Mod 24 Dim firstblock As String Dim secondblock As String Dim thirdblock As String Dim fourthblock As String firstblock = 0 secondblock = 0 thirdblock = 0 fourthblock = 0 Select Case order Case 0 firstblock = "A" secondblock = "B" thirdblock = "C" fourthblock = "D" Case 1 firstblock = "A" secondblock = "B" thirdblock = "D" fourthblock = "C" Case 2 firstblock = "A" secondblock = "C" thirdblock = "B" fourthblock = "D" Case 3 firstblock = "A" secondblock = "C" thirdblock = "D" fourthblock = "B" Case 4 firstblock = "A" secondblock = "D" thirdblock = "B" fourthblock = "C" Case 5 firstblock = "A" secondblock = "D" thirdblock = "C" fourthblock = "B" Case 6 firstblock = "B" secondblock = "A" thirdblock = "C" fourthblock = "D" Case 7 firstblock = "B" secondblock = "A" thirdblock = "D" fourthblock = "C" Case 8 firstblock = "B" secondblock = "C" thirdblock = "A" fourthblock = "D" Case 9 firstblock = "B" secondblock = "C" thirdblock = "D" fourthblock = "A" Case 10 firstblock = "B" secondblock = "D" thirdblock = "A" fourthblock = "C" Case 11 firstblock = "B" secondblock = "D" thirdblock = "C" fourthblock = "A" Case 12 firstblock = "C" secondblock = "A" thirdblock = "B" fourthblock = "D" Case 13 firstblock = "C" secondblock = "A" thirdblock = "D" fourthblock = "B" Case 14 firstblock = "C" secondblock = "B" thirdblock = "A" fourthblock = "D" Case 15 firstblock = "C" secondblock = "B" thirdblock = "D" fourthblock = "A" Case 16 firstblock = "C" secondblock = "D" thirdblock = "A" fourthblock = "B" Case 17 firstblock = "C" secondblock = "D" thirdblock = "B" fourthblock = "A" Case 18 firstblock = "D" secondblock = "A" thirdblock = "B" fourthblock = "C" Case 19 firstblock = "D" secondblock = "A" thirdblock = "C" fourthblock = "B" Case 20 firstblock = "D" secondblock = "B" thirdblock = "A" fourthblock = "C" Case 21 firstblock = "D" secondblock = "B" thirdblock = "C" fourthblock = "A" Case 22 firstblock = "D" secondblock = "C" thirdblock = "A" fourthblock = "B" Case 23 firstblock = "D" secondblock = "C" thirdblock = "B" fourthblock = "A" End Select Dim z As Integer = 0 Dim v As Integer = 8 'Block A Dim blocka(16) As UInt16 While z < 16 blocka(z) = BitConverter.ToUInt16(pkm, v) z = z + 1 v = v + 2 End While z = 0 v = 40 'Block B Dim blockb(16) As UInt16 While z < 16 blockb(z) = BitConverter.ToUInt16(pkm, v) z = z + 1 v = v + 2 End While z = 0 'Block C v = 72 Dim blockc(16) As UInt16 While z < 16 blockc(z) = BitConverter.ToUInt16(pkm, v) z = z + 1 v = v + 2 End While z = 0 'Block D Dim blockd(16) As UInt16 v = 104 While z < 16 blockd(z) = BitConverter.ToUInt16(pkm, v) z = z + 1 v = v + 2 End While z = 0 srnd(checksum) Dim byter(16) As UInt16 z = 0 v = 8 Select Case firstblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While Case "B" While z < 16 byter(z) = blockb(z) Xor rand() z = z + 1 End While Case "C" While z < 16 byter(z) = blockc(z) Xor rand() z = z + 1 End While Case "D" While z < 16 byter(z) = blockd(z) Xor rand() z = z + 1 End While End Select z = 0 v = 8 While z < 16 pkm(v) = byter(z) And 255 pkm(v + 1) = byter(z) >> 8 z = z + 1 v = v + 2 End While z = 0 v = 40 Select Case secondblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While Case "B" While z < 16 byter(z) = blockb(z) Xor rand() z = z + 1 End While Case "C" While z < 16 byter(z) = blockc(z) Xor rand() z = z + 1 End While Case "D" While z < 16 byter(z) = blockd(z) Xor rand() z = z + 1 End While End Select z = 0 While z < 16 pkm(v) = byter(z) And 255 pkm(v + 1) = byter(z) >> 8 z = z + 1 v = v + 2 End While z = 0 v = 72 Select Case thirdblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While Case "B" While z < 16 byter(z) = blockb(z) Xor rand() z = z + 1 End While Case "C" While z < 16 byter(z) = blockc(z) Xor rand() z = z + 1 End While Case "D" While z < 16 byter(z) = blockd(z) Xor rand() z = z + 1 End While End Select z = 0 While z < 16 pkm(v) = byter(z) And 255 pkm(v + 1) = byter(z) >> 8 z = z + 1 v = v + 2 End While z = 0 v = 104 Select Case fourthblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While Case "B" While z < 16 byter(z) = blockb(z) Xor rand() z = z + 1 End While Case "C" While z < 16 byter(z) = blockc(z) Xor rand() z = z + 1 End While Case "D" While z < 16 byter(z) = blockd(z) Xor rand() z = z + 1 End While End Select z = 0 While z < 16 pkm(v) = byter(z) And 255 pkm(v + 1) = byter(z) >> 8 z = z + 1 v = v + 2 End While z = 0 Return pkm End Function Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 11, 2018 Author Share Posted February 11, 2018 12 hours ago, theSLAYER said: @Regnum This is my encrypt code. Since this was made years back, there's probably definitely better ways to optimize the code, so you can keep that in mind if you're gonna adapt it. Reveal hidden contents Public Function encrypt(ByVal pkm() As Byte) Dim pid As UInt32 = 0 Dim checksum As UInt16 = 0 pid = BitConverter.ToUInt32(pkm, 0) checksum = BitConverter.ToUInt16(pkm, 6) Dim order As Integer = (pid >> (13) And 31) Mod 24 Dim firstblock As String Dim secondblock As String Dim thirdblock As String Dim fourthblock As String firstblock = 0 secondblock = 0 thirdblock = 0 fourthblock = 0 Select Case order Case 0 firstblock = "A" secondblock = "B" thirdblock = "C" fourthblock = "D" Case 1 firstblock = "A" secondblock = "B" thirdblock = "D" fourthblock = "C" Case 2 firstblock = "A" secondblock = "C" thirdblock = "B" fourthblock = "D" Case 3 firstblock = "A" secondblock = "C" thirdblock = "D" fourthblock = "B" Case 4 firstblock = "A" secondblock = "D" thirdblock = "B" fourthblock = "C" Case 5 firstblock = "A" secondblock = "D" thirdblock = "C" fourthblock = "B" Case 6 firstblock = "B" secondblock = "A" thirdblock = "C" fourthblock = "D" Case 7 firstblock = "B" secondblock = "A" thirdblock = "D" fourthblock = "C" Case 8 firstblock = "B" secondblock = "C" thirdblock = "A" fourthblock = "D" Case 9 firstblock = "B" secondblock = "C" thirdblock = "D" fourthblock = "A" Case 10 firstblock = "B" secondblock = "D" thirdblock = "A" fourthblock = "C" Case 11 firstblock = "B" secondblock = "D" thirdblock = "C" fourthblock = "A" Case 12 firstblock = "C" secondblock = "A" thirdblock = "B" fourthblock = "D" Case 13 firstblock = "C" secondblock = "A" thirdblock = "D" fourthblock = "B" Case 14 firstblock = "C" secondblock = "B" thirdblock = "A" fourthblock = "D" Case 15 firstblock = "C" secondblock = "B" thirdblock = "D" fourthblock = "A" Case 16 firstblock = "C" secondblock = "D" thirdblock = "A" fourthblock = "B" Case 17 firstblock = "C" secondblock = "D" thirdblock = "B" fourthblock = "A" Case 18 firstblock = "D" secondblock = "A" thirdblock = "B" fourthblock = "C" Case 19 firstblock = "D" secondblock = "A" thirdblock = "C" fourthblock = "B" Case 20 firstblock = "D" secondblock = "B" thirdblock = "A" fourthblock = "C" Case 21 firstblock = "D" secondblock = "B" thirdblock = "C" fourthblock = "A" Case 22 firstblock = "D" secondblock = "C" thirdblock = "A" fourthblock = "B" Case 23 firstblock = "D" secondblock = "C" thirdblock = "B" fourthblock = "A" End Select Dim z As Integer = 0 Dim v As Integer = 8 'Block A Dim blocka(16) As UInt16 While z < 16 blocka(z) = BitConverter.ToUInt16(pkm, v) z = z + 1 v = v + 2 End While z = 0 v = 40 'Block B Dim blockb(16) As UInt16 While z < 16 blockb(z) = BitConverter.ToUInt16(pkm, v) z = z + 1 v = v + 2 End While z = 0 'Block C v = 72 Dim blockc(16) As UInt16 While z < 16 blockc(z) = BitConverter.ToUInt16(pkm, v) z = z + 1 v = v + 2 End While z = 0 'Block D Dim blockd(16) As UInt16 v = 104 While z < 16 blockd(z) = BitConverter.ToUInt16(pkm, v) z = z + 1 v = v + 2 End While z = 0 srnd(checksum) Dim byter(16) As UInt16 z = 0 v = 8 Select Case firstblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While Case "B" While z < 16 byter(z) = blockb(z) Xor rand() z = z + 1 End While Case "C" While z < 16 byter(z) = blockc(z) Xor rand() z = z + 1 End While Case "D" While z < 16 byter(z) = blockd(z) Xor rand() z = z + 1 End While End Select z = 0 v = 8 While z < 16 pkm(v) = byter(z) And 255 pkm(v + 1) = byter(z) >> 8 z = z + 1 v = v + 2 End While z = 0 v = 40 Select Case secondblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While Case "B" While z < 16 byter(z) = blockb(z) Xor rand() z = z + 1 End While Case "C" While z < 16 byter(z) = blockc(z) Xor rand() z = z + 1 End While Case "D" While z < 16 byter(z) = blockd(z) Xor rand() z = z + 1 End While End Select z = 0 While z < 16 pkm(v) = byter(z) And 255 pkm(v + 1) = byter(z) >> 8 z = z + 1 v = v + 2 End While z = 0 v = 72 Select Case thirdblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While Case "B" While z < 16 byter(z) = blockb(z) Xor rand() z = z + 1 End While Case "C" While z < 16 byter(z) = blockc(z) Xor rand() z = z + 1 End While Case "D" While z < 16 byter(z) = blockd(z) Xor rand() z = z + 1 End While End Select z = 0 While z < 16 pkm(v) = byter(z) And 255 pkm(v + 1) = byter(z) >> 8 z = z + 1 v = v + 2 End While z = 0 v = 104 Select Case fourthblock Case "A" While z < 16 byter(z) = blocka(z) Xor rand() z = z + 1 End While Case "B" While z < 16 byter(z) = blockb(z) Xor rand() z = z + 1 End While Case "C" While z < 16 byter(z) = blockc(z) Xor rand() z = z + 1 End While Case "D" While z < 16 byter(z) = blockd(z) Xor rand() z = z + 1 End While End Select z = 0 While z < 16 pkm(v) = byter(z) And 255 pkm(v + 1) = byter(z) >> 8 z = z + 1 v = v + 2 End While z = 0 Return pkm End Function I keep getting a System.OverflowException at the Select Case firstblock. 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theSLAYER Posted February 12, 2018 Share Posted February 12, 2018 7 hours ago, Regnum said: I keep getting a System.OverflowException at the Select Case firstblock. you may need to set your own variables public and correct in other instances besides the function. How are you reading the file, and what variable is handling the Pokemon file you're reading (I'm getting the feeling you haven't loaded the file) Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 12, 2018 Author Share Posted February 12, 2018 14 hours ago, theSLAYER said: you may need to set your own variables public and correct in other instances besides the function. How are you reading the file, and what variable is handling the Pokemon file you're reading (I'm getting the feeling you haven't loaded the file) The file is being loaded with: Dim myFile = OpenFileDialog1.FileName Dim pkx() As Byte = My.Computer.FileSystem.ReadAllBytes(myFile) Dim ekx = encrypt(pkx) Link to comment Share on other sites More sharing options...
theSLAYER Posted February 12, 2018 Share Posted February 12, 2018 1 hour ago, Regnum said: The file is being loaded with: Dim myFile = OpenFileDialog1.FileName Dim pkx() As Byte = My.Computer.FileSystem.ReadAllBytes(myFile) Dim ekx = encrypt(pkx) Not that I'm very good at programming, but maybe you wannaDim ekx() as byte = encrypt(pkx) Maybe also want to do a "if then" logic tests in your routine, as Gen 6/7 encrypt is gonna be different from the Gen5 routine I showed you. Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 13, 2018 Author Share Posted February 13, 2018 (edited) 5 hours ago, theSLAYER said: Not that I'm very good at programming, but maybe you wannaDim ekx() as byte = encrypt(pkx) Maybe also want to do a "if then" logic tests in your routine, as Gen 6/7 encrypt is gonna be different from the Gen5 routine I showed you. I tried that, but the error persists. I then tried: Private Sub toEnc() Dim myFile As String = OpenFileDialog1.FileName Dim myBytes As Byte() = My.Computer.FileSystem.ReadAllBytes(myFile) Dim txtTemp As New System.Text.StringBuilder() For Each myByte As Byte In myBytes txtTemp.Append(myByte.ToString("X2")) Next RichTextBox1.Text = txtTemp.ToString() Dim myData = RichTextBox1.Text Dim pkx As Byte() = HexStringToByteArray(myData) Dim ekx() As Byte = encrypt(pkx) End Sub Private Shared Function HexStringToByteArray(ByRef strInput As String) As Byte() Dim length As Integer Dim bOutput As Byte() Dim c(1) As Integer length = strInput.Length / 2 ReDim bOutput(length - 1) For i As Integer = 0 To (length - 1) For j As Integer = 0 To 1 c(j) = Asc(strInput.Chars(i * 2 + j)) If ((c(j) >= Asc("0")) And (c(j) <= Asc("9"))) Then c(j) = c(j) - Asc("0") ElseIf ((c(j) >= Asc("A")) And (c(j) <= Asc("F"))) Then c(j) = c(j) - Asc("A") + &HA ElseIf ((c(j) >= Asc("a")) And (c(j) <= Asc("f"))) Then c(j) = c(j) - Asc("a") + &HA End If Next j bOutput(i) = (c(0) * &H10 + c(1)) Next i Return (bOutput) End Function Edited February 13, 2018 by Regnum Link to comment Share on other sites More sharing options...
theSLAYER Posted February 13, 2018 Share Posted February 13, 2018 before the select case, get your program to prompt a message box, and display the PID values. (to ensure that the program is indeed reading the file) <btw I figured you already know, but just to be sure: PKHeX can export ekx files> Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 13, 2018 Author Share Posted February 13, 2018 (edited) 5 minutes ago, theSLAYER said: before the select case, get your program to prompt a message box, and display the PID values. (to ensure that the program is indeed reading the file) It gave me 0x35C7F1EE, but the pk5 file in HxD says 0xEEF1C735. Edited February 13, 2018 by Regnum Link to comment Share on other sites More sharing options...
theSLAYER Posted February 13, 2018 Share Posted February 13, 2018 1 hour ago, Regnum said: It gave me 0x35C7F1EE, but the pk5 file in HxD says 0xEEF1C735. Remember that the data is in little endian and needs to be swapped. At least that part is more of less working properly. now, slowly increment/push forward to see which sub or function isn't working Link to comment Share on other sites More sharing options...
RenegadeRaven Posted February 14, 2018 Author Share Posted February 14, 2018 (edited) 22 hours ago, theSLAYER said: Remember that the data is in little endian and needs to be swapped. At least that part is more of less working properly. now, slowly increment/push forward to see which sub or function isn't working I tried incrementing forward as you said and found that byter(z) = blocka(z) Xor rand() is equal to byter(z) = 0xAA60CFF and byter() is UInt16. So I changed byter(z) = block_(z) Xor rand() to byter(z) = CType((block_(z) Xor rand()), System.UInt16), now the function rand() is giving me the System.OverflowException error. Edited February 14, 2018 by Regnum Link to comment Share on other sites More sharing options...
theSLAYER Posted February 14, 2018 Share Posted February 14, 2018 4 hours ago, Regnum said: I tried incrementing forward as you said and found that byter(z) = blocka(z) Xor rand() is equal to byter(z) = 0xAA60CFF and byter() is UInt16. So I changed byter(z) = block_(z) Xor rand() to byter(z) = CType((block_(z) Xor rand()), System.UInt16), now the function rand() is giving me the System.OverflowException error. So you changed it.. Because it was giving you a value? Link to comment Share on other sites More sharing options...
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